정올 569 : 배열2-자가진단6

My Solution

#include<stdio.h>
int main(void){
    int score[5][4]={0,};
    int i, j, sum, count=0;
    for(i=0;i<5;i++){
        for(j=0;j<4;j++){
            scanf("%d",&score[i][j]);
        }
    }
    for(i=0;i<5;i++){
        for(j=0;j<4;j++){
            sum+=score[i][j];            
        }
        if(sum/4>=80){
            printf("pass\n");
            count++;
        }
        else{
            printf("fail\n");
        }
        sum=0;
    }
    printf("Successful : %d", count);
    return 0;
    
}