518 : 연산자-자가진단1

My Solution : 

#include<stdio.h>
int main(void){
    int num1=0,num2=0,num3=0;
    int sum=0;
    double avg=0;
    printf("정수 3개 입력 : ");
    scanf("%d %d %d",&num1,&num2,&num3);
    sum=num1+num2+num3;
    printf("sum : %d\n",sum);
    avg=sum/3;
    printf("avg : %.0f",avg);
    return 0;
}